4.78x^2-10.04x+2.96=0

Solution for 4.78x^2-10.04x+2.96=0 equation:

4.78x^2-10.04x+2.96=0

a = 4.78; b = -10.04; c = +2.96;
Δ = b2-4ac
Δ = -10.042-4·4.78·2.96
Δ = 44.2064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.04)-\sqrt{44.2064}}{2*4.78}=\frac{10.04-\sqrt{44.2064}}{9.56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.04)+\sqrt{44.2064}}{2*4.78}=\frac{10.04+\sqrt{44.2064}}{9.56}
$